https://www.amino.dk:443/forums/17419.aspx?utm_source=rss&utm_medium=rss&utm_campaign=rss-feedDen frie debat hvor alt inden for iværksætteri diskuteres. Har du noget fedt på hjertet så slå et indlæg op. daCommunityServer 2008.5 SP2 (Debug Build: 40407.4157)https://www.amino.dk:443/forums/thread/1810569.aspx?utm_source=rss&utm_medium=rss&utm_campaign=rss-feedMon, 25 Jun 2018 22:51:39 GMT426ea658-be4c-49d4-a865-b6f342788162:1810569Aqsa Shahbaz0https://www.amino.dk:443/forums/thread/1810569.aspx?utm_source=rss&utm_medium=rss&utm_campaign=rss-feedhttps://www.amino.dk:443/forums/commentrss.aspx?SectionID=17419&PostID=1810569&utm_source=rss&utm_medium=rss&utm_campaign=rss-feed<p>Bruger du formlen; <br /> <br /> X-bar- z_1-alfa* kvodrod af s^2/n? </p>https://www.amino.dk:443/forums/thread/1810559.aspx?utm_source=rss&utm_medium=rss&utm_campaign=rss-feedMon, 25 Jun 2018 21:32:01 GMT426ea658-be4c-49d4-a865-b6f342788162:1810559Aqsa Shahbaz0https://www.amino.dk:443/forums/thread/1810559.aspx?utm_source=rss&utm_medium=rss&utm_campaign=rss-feedhttps://www.amino.dk:443/forums/commentrss.aspx?SectionID=17419&PostID=1810559&utm_source=rss&utm_medium=rss&utm_campaign=rss-feed<p>Kan du vise mig udregning?</p>https://www.amino.dk:443/forums/thread/1810546.aspx?utm_source=rss&utm_medium=rss&utm_campaign=rss-feedMon, 25 Jun 2018 19:44:57 GMT426ea658-be4c-49d4-a865-b6f342788162:1810546Jesper_nl0https://www.amino.dk:443/forums/thread/1810546.aspx?utm_source=rss&utm_medium=rss&utm_campaign=rss-feedhttps://www.amino.dk:443/forums/commentrss.aspx?SectionID=17419&PostID=1810546&utm_source=rss&utm_medium=rss&utm_campaign=rss-feed<p><blockquote><div><div class="ico_reply_quote"></div> <strong>Aqsa Shahbaz:</strong></div><div></p> <p>Hej <br /> <br /> Suppose 121 gamblers in Las Vegas are chosen at random and their lifetime winnings or losses have an average of -4,700 and a standard deviation of 43,000. <br /> <br /> Jeg skal bestemme konfidense interval n&aring;r alfa er 95%. <br /> <br /> Kan nogle hj&aelig;lpe mig?</p> <p></div></blockquote></p> <p>Har du ikke en formelsamling??</p> <p>&nbsp;</p> <p>Men ellers er svaret (ved normalfordeling) lig med 7.662 p&aring; hver side af middelv&aelig;rdi.</p> <p></p> <p>&nbsp;</p> <p></p><div class="clearBoth"></div>https://www.amino.dk:443/forums/thread/1810508.aspx?utm_source=rss&utm_medium=rss&utm_campaign=rss-feedMon, 25 Jun 2018 14:55:08 GMT426ea658-be4c-49d4-a865-b6f342788162:1810508Aqsa Shahbaz0https://www.amino.dk:443/forums/thread/1810508.aspx?utm_source=rss&utm_medium=rss&utm_campaign=rss-feedhttps://www.amino.dk:443/forums/commentrss.aspx?SectionID=17419&PostID=1810508&utm_source=rss&utm_medium=rss&utm_campaign=rss-feed<p>Hej <br /> <br /> Suppose 121 gamblers in Las Vegas are chosen at random and their lifetime winnings or losses have an average of -4,700 and a standard deviation of 43,000. <br /> <br /> Jeg skal bestemme konfidense interval når alfa er 95%. <br /> <br /> Kan nogle hjælpe mig? </p>